## 3-15-15. George Howard Darwin to H. Poincaré

June 21.01

Newnham Grange–Cambridge

Dear Monsieur Poincaré,

I do not see how it is possible to solve the question without carrying
the investigation through completely^{1}^{1}
1
Variant: “almost completely”. to
the second order of small quantities. I had come to this conclusion
before hearing from you,^{2}^{2}
2
See Poincaré to Darwin,
§ 3-15-14. but when you said that my figure afforded the
means of deciding the question of increase of momentum
I thought you must be
right, and besides forgot my previous reflections on the subject.^{3}^{3}
3
See
Poincaré to Darwin,
§ 3-15-12.

As it is possible to carry the theory of the figure of the earth to the second order of small quantities by means of spherical harmonics, so I think it is possible to proceed to the second order here with ellipsoidal harmonics. I believe I see how it is to be done numerically, proceeding from a specified Jacobian ellipsoid; but I do not see much prospect of doing it analytically. But the arithmetic would be very heavy, since it would involve the determination of a considerable number of integrals by quadratures—integrals theoretically perhaps expressible in Elliptic integrals, but with coefficients of stupendous complication. The fundamental difficulty is thus. Suppose we have an inequality on the ellipsoid represented by (curvilinear normal)

$$\delta n=p.\epsilon {\U0001d513}_{3}(\mu ){\U0001d5a2}_{3}(\varphi )\mathit{\hspace{1em}}\left[{3}^{\text{rd}}\text{zonal}\right]$$ |

($p\u27c2$ on tangent plane); then we have to find the mass standing on unit area of the ellipsoid as far as squares of $\epsilon $.

I have obtained the expression in question. The term in $\epsilon $ is obvious by ellipsoidal analysis — that in ${\epsilon}^{2}$ depends on $p{[{\U0001d513}_{3}(\mu ){\U0001d5a2}_{3}(\varphi )]}^{2}$ multiplied by a complicated function of the two coordinates $\mu $, $\varphi $.

In order to proceed further, this function must be expressed in
ellipsoidal harmonics and it will involve harmonics of orders 0, 2,
4, 6…and of even orders of tesserality.^{4}^{4}
4
Darwin
(1903, 253) linked the even-order harmonics to
the figure’s symmetry.

I believe that by quadratures & a sufficient degree of labour I can get out those harmonics – but whether or not I have the patience to do so, is another question.

This result shows that we must start by supposing that the figure of
equilibrium consists not only of a 3^{rd} harmonic of amplitude
$\epsilon $ (whose square is retained), but also of harmonics of
orders 0, 2, 4, 6…& of amplitudes unknown save that
they are of the order ${\epsilon}^{2}$.^{5}^{5}
5
Variant: “save that
it is of the second order ${\epsilon}^{2}$.”
These new harmonics will affect the moment of
inertia.

The harmonic 0 is what Kelvin calls a focaloid shell & indicates that
the elevation of the 3^{rd} zonal must be computed from a surface
confocal to the primitive ellipsoid — otherwise the mass of the pear
will not be equal to that of the ellipsoid.^{6}^{6}
6
The focaloid
shell was defined by
Thomson (1879, §494 g)
as an
infinitely-thin shell bounded by two concentric similar ellipsoidal
surfaces. He employed it to prove a theorem attributed to MacLaurin,
and used here by Darwin, according to which any two confocal
homogeneous solid ellipsoids of equal mass give rise to equal
attraction. Clairaut’s theory of heterogeneous masses also employed
focaloid shells; see the notes to Darwin to Poincaré, 31.07.1901
(§ 3-15-17). This
harmonic then enters in the moment of inertia, as also does that of
order 2; the remaining harmonics do not do so.^{7}^{7}
7
Variant: “do
not do so. Hence if I worked out these two only I could decide
the question of the moment of momentum
with”.^{8}^{8}
8
Cf. Poincaré to Darwin
(§ 3-15-19), where Poincaré shows
that ${\xi}_{3}$ (the coefficient of ${R}_{2,0}^{1}={\U0001d513}_{2}$ in the
notation of Poincaré (1902), here $\eta $) and ${\xi}_{4}$
(the coefficient of ${R}_{2,2}^{1}={\U0001d513}_{2}^{2}$ in Poincaré’s
notation, here $\zeta $) enter the computation with the second order
while the third zonal enters with the first order.

If I assume these difficulties overcome, then I think (also with sufficient labour) I can overcome the remainder.

In order to find the gravitational terms I should proceed thus:

Draw a concentric and similar ellipsoid touching the stalk of
the pear. It is a Jacobian ellipsoid, but its mass depends on the
determination of the exact figure of the pear. Nevertheless I can
find the expression for its internal gravity although that
expression involves $\epsilon $.^{9}^{9}
9
On Darwin’s solution see
Darwin to Poincaré, 12.08.1901
(§ 3-15-23).

Consider the shaded pear to consist of negative matter; then by quadratures I can find the energy due to the gravitation of the larger ellipsoid and this shaded matter.

The mutual energy of the layer as far as it depends on the
harmonics 0, 2, 4, 6 …is determinable at once by harmonic
analysis. That
corresponding to the 3^{rd} zonal is to the first order the same as
tho’ it were concentrated on the surface. To go to the second order we
must first concentrate in surface density on ellipsoid and then deform
that surface density — so as to bring it to stand half way between
the ellipsoid & the true surface.^{10}^{10}
10
This is the double layer
strategy used later by Poincaré; see Poincaré to Darwin
(§ 3-15-25).
This last may be done thus: If we have a layer of surface density with
potential ${v}_{(+)}$ externally and potential ${v}_{(-)}$ internally, the
force acting on an element $d\sigma $ is^{11}^{11}
11
The second factor
involves Poisson’s equation
(Darwin 1901, 507); the last
fraction has been corrected from $d{v}_{(-1)}/dn$.

$$-\frac{1}{2}\left(\frac{d{v}_{(+)}}{dn}+\frac{d{v}_{(-)}}{dn}\right)\cdot \frac{1}{4\pi}\left(\frac{d{v}_{(+)}}{dn}-\frac{d{v}_{(-)}}{dn}\right)\cdot d\sigma .$$ |

If the element is carried outwards through a distance $\frac{1}{2}\delta n$, the work done is

$$\frac{1}{16\pi}\left[{\left(\frac{d{v}_{(+)}}{dn}\right)}^{2}-{\left(\frac{d{v}_{(-)}}{dn}\right)}^{2}\right]\delta n\cdot d\sigma $$ |

Integrating all over the surface one may obtain the whole work done in deformation.

In this sketch of procedure I have left a good deal vague, but I think the processes involved are legitimate.

I do not see that any analytical skill could make the processes necessary other than very laborious – unless indeed it were possible to obtain expressions for harmonic functions applicable to the pear-shaped figure.

I am afraid this letter is very ill expressed, but I hope it is intelligible and that you will not detect faults of principle.

I remain, Yours sincerely

G.H. Darwin

ALS 8p. Collection particulière, Paris 75017.

Time-stamp: "14.09.2016 18:02"

## References

- The pear-shaped figure of equilibrium of a rotating mass of liquid. Proceedings of the Royal Society of London 69, pp. 147–148. External Links: Link Cited by: footnote 11.
- The approximate determination of the form of Maclaurin’s spheroid. Transactions of the American Mathematical Society 4 (2), pp. 113–133. Cited by: footnote 4.
- Sur la stabilité de l’équilibre des figures piriformes affectées par une masse fluide en rotation. Philosophical Transactions of the Royal Society A 198, pp. 333–373. External Links: Link Cited by: footnote 8.
- Treatise on Natural Philosophy. Cambridge University Press, Cambridge. External Links: Link Cited by: footnote 6.